Oct 1, 2012 · In Regex, . refers to any character, be it a number, an aplhabet character, or any other special character. * means zero or more times.

Dec 8, 2018 · The regex compiles fine, and there are already JUnit tests that show how it works. It's just that I'm a bit confused about why the first question mark and colon are there.

While writing this answer, I had to match exclusively on linebreaks instead of using the s-flag (dotall - dot matches linebreaks). The sites usually used to test regular expressions behave …

Dec 6, 2012 · That regex "\\s*,\\s*" means: \s* any number of whitespace characters a comma \s* any number of whitespace characters which will split on commas and consume any spaces …

By putting ^ at the beginning of your regex and $ at the end, you ensure that no other characters are allowed before or after your regex. For example, the regex [0-9] matches the strings "9" as …

May 14, 2019 · I need a regex which will allow only A-Z, a-z, 0-9, the _ character, and dot (.) in the input. I tried: [A-Za-z0-9_.] But, it did not work. How can I fix it?

I need to extract from a string a set of characters which are included between two delimiters, without returning the delimiters themselves. A simple example should be helpful: Target: …

Apr 13, 2013 · Note that your regex would have worked too if it was written as \d \w|\d instead of \d|\d \w. This is because in your case, once the regex matches the first option, \d, it ceases to …

Jan 28, 2015 · I'd like to get the single strings of a pipe-separated string, with "pipe escaping" support, e.g.: fielda|field b |field\|with\|pipe\|inside would get me: array ...

Be aware that the first ^ in this answer gives the regex a completely different meaning: It makes the regular expression look only for matches starting from the beginning of the string.