Sep 19, 2018 · All your return c.most_common()[-1] statement does is call c.most_common and return the last value in the resulting list, which would give you the least common item in that …

Dec 3, 2016 · A list of lists named xss can be flattened using a nested list comprehension: flat_list = [ x for xs in xss for x in xs ] The above is equivalent to: flat_list = [] for xs in xss: for x in xs: …

Apr 11, 2011 · Agree with @Bogdan. This answer creates a string in which the list elements are joined together with no whitespace or comma in between. You can use ', '.join(list1) to join the …

Nov 1, 2011 · def make_unique(original_list): unique_list = [] [unique_list.append(obj) for obj in original_list if obj not in unique_list] return unique_list Some may consider list comprehension …

Sep 20, 2010 · List slicing is quite flexible as it allows to replace a range of entries in a list with a range of ...

Create a list of keys/columns - object method to_list() and the Pythonic way: my_dataframe.keys().to_list() list(my_dataframe.keys()) Basic iteration on a DataFrame …

Mar 21, 2014 · If you want a set of items in either list but not both lists use the symmetric difference operator '^'. [1,2,3,4,5] ^ [3,4,5,6,7] = [1,2,6,7] The symmetric difference operator, …

Jan 12, 2009 · Using e.g. List<Point> list, it would be necessary to instead say Point temp=list[3]; temp.x+=q; list[3]=temp;. It would be helpful if List<T> had a method Update<TP>(int index, …

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joined_list = [item for list_ in [list_one, list_two] for item in list_] It has all the advantages of the newest approach of using Additional Unpacking Generalizations - i.e. you can concatenate an …